The problem is How many millimeters of liquid water should be produced by the combustion of octane(C8H18) in abundant oxygen? ume that the volumes for both liquids are measured at 20 degrees Celsius, where the densities are .07025 g/ml for octane and .9982 g/ml for water. First, what is the equation for the problem? Second, how do you solve it? What are the steps? Answers aren't needed unless you want to give them:) Thanks.
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